I was trying to make a raster image from an irregularly spaced point database. The data looks like-
> head(s100_ras) x y z 1 267573.9 2633781 213.29545 2 262224.4 2633781 69.78261 3 263742.7 2633781 51.21951 4 259328.4 2633781 301.98413 5 264109.8 2633781 141.72414 6 255094.8 2633781 88.90244
I want these 'z' values within a mesh which I created by
# Create a fine mesh grid my_mesh=expand.grid(seq(min(s100_ras$Y),max(s100_ras$Y),l=100), seq(min(s100_ras$X),max(s100_ras$X),l=100))
I also want the z-values to be assigned as 'NA' for those mesh points that are outside the data points. The points over the mesh looks like this: https://drive.google.com/file/d/0B6GUNg-8d30vYzlwTkhvaHBFTnc/edit?usp=sharing when I plot
plot(my_mesh) points(s100_ras$Y, s100_ras$X, pch="*", col='blue')
The problem is that I'm not sure how to build on this, the following steps don't work because my mesh grid and data points are not of the same scale!!
library(rgdal) library(raster) xyz<-cbind(my_mesh, s100_ras) r <- rasterFromXYZ(xyz) image(r)
If I try to make a raster just by using the data points (without any mesh), R throws an error since my data is irregularly spaced!
library(sp) s100_ras <- data.frame(expand.grid(x = s100_ras$Y, y = s100_ras$X), z = as.vector(s100_ras$mean)) coordinates(s100_ras) <- ~x+y proj4string(s100_ras) <- CRS("+proj=utm +zone=46 +datum=WGS84") gridded(s100_ras) = TRUE suggested tolerance minimum: 0.916421 Error in points2grid(points, tolerance, round) : dimension 1 : coordinate intervals are not constant
Moreover, I was trying to play with 'rasterize' function (for irregular grids) of 'raster package', but couldn't get a way with it :(. I know how to interpolate and make a regular grid, but for the sake of originality, I want to AVOID interpolation. Is it possible to make a raster of irregularly spaced data points without idw or kriging methods?