I was looking in Fiona to get for each feature its extent but I didn't find how.

I have try to far to do something like below

import fiona

with fiona.open('countries/ne_10m_admin_0_countries.shp', 'r') as source:
    for f in source:
        geom = f['geometry']
        print geom

I was expecting to get a method for this at the f variable level. After some documentation reading, I've seen that f is a pure python record. So at the end, how with Fiona can I get the extent (or bounding box) of each feature geometry?

PS: I already know the pure GDAL/OGR python solution so I expect a Fiona solution please

  • I would be really interested in seeing the OGR python solution. I'm going through the documentation, and it looks like extents for layers and features are handled differently in OGR. – midfield99 Apr 16 '14 at 0:22

I'd do it like this:

def explode(coords):
    """Explode a GeoJSON geometry's coordinates object and yield coordinate tuples.
    As long as the input is conforming, the type of the geometry doesn't matter."""
    for e in coords:
        if isinstance(e, (float, int, long)):
            yield coords
            for f in explode(e):
                yield f

def bbox(f):
    x, y = zip(*list(explode(f['geometry']['coordinates'])))
    return min(x), min(y), max(x), max(y)
  • Just in case it's not obvious: the approach above works for deserialized GeoJSON generally and isn't limited to use with Fiona. – sgillies Mar 23 '14 at 15:33
  • I made a slight change to use ESRI's json and this solved one of my problems as well. Thanks! – CMPalmer Apr 3 '16 at 18:40

You need to use the function shape of Shapely:

from shapely.geometry import shape
c = fiona.open("ne_10m_admin_0_countries.shp")
# first record
country = c.next()
print "country name :",country['properties']['NAME']
country name : Aruba
# shape(country['geometry']) -> shapely geometry
print "bounds:", shape(country['geometry']).bounds
bounds: (-70.062408006999874, 12.417669989000046, -69.876820441999939, 12.632147528000104)
  • I've accepted @sgillies answer because no lib dependency but I appreciate also your answer. Thanks – ThomasG77 Mar 23 '14 at 11:07
  • It does Thomas, but there you go, it's just not implicit! – Hairy Oct 23 '17 at 14:21

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