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Since you are dealing with point data, the results of both expressions of $x and x($geometry) are identical. Same applied to $y and y($geometry). I tested the behavior of both expressions on my point grid data and I found that both them produced the same results as you can see below: In the table above the coordinates in X and Y fields were calculated using ...


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Solved by Mike Mike's solution here Thanks to @Mike to his help. I put the solution that Mike did in codesandbox (just in case, in a future may not be available) index.html <!DOCTYPE html> <html lang="en"> <head> <title>Simple Map</title> <!-- The line below is only needed for old environments like Internet ...


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Currently it does not seem to be supported in PROJ. With the latest version, I used the projinfo command: $ projinfo -s "WGS84" -t "epsg:5819" Candidate operations found: 1 ------------------------------------- Operation n°1: unknown id, Inverse of Null geographic offset from WGS 84 to WGS 84 + EPSG topocentric example A, 0 m, World PROJ string: Error ...


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You cannot get the extent from the center and number of pixels alone. These images all have the same center and number of pixels: You also need to know the resolution (the distance on the ground covered by each pixel) and the rotation (was the image taken with north at the top)


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I believe the information you want is available via these tags: Gimbal Roll Degree : +0.00 Gimbal Yaw Degree : +15.90 Gimbal Pitch Degree : -90.00 Flight Roll Degree : -8.70 Flight Yaw Degree : +15.30 Flight Pitch Degree : -6.20 Flight X Speed : +0.00 Flight Y ...


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I have got the answer for my question today as: var district = ee.FeatureCollection('ft:1PA2zwArj8EsplrX9eMxJ2H_TICyyx855KPnbJhC1','geometry') .filter(ee.Filter.eq('name','Begusarai')); var boundbox = district.geometry().bounds(); Map.centerObject(bbox); Map.addLayer(bbox); Map.addLayer(geometry, {color: 'red'}); print(district); // return the list of ...


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Your coords are: [,1] [,2] [1,] 14.650 40.350 [2,] 13.600 39.350 [3,] 0.033 -78.717 [4,] 37.017 -2.383 [5,] 46.837 -113.966 but coordinate matrices are always X then Y, ie Longitude then Latitude. Your NAs are coming from column 2 being more than 90 or less than -90, which are not valid latitudes. extract(r, coords[,2:...


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I don't think there are practical limitations to ned2geodetic. The conversion from LLA to ECEF coordinates has closed form solution. The rotation of NED vector to ECEF has closed form solution. Vector addition in ECEF is trivial. Conversion of ECEF coordinates to LLA as implemented in Matlab is not closed form solution. However, the algorithm employed is ...


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The approach you're looking for is called monoplotting in photogrammetry. If given your assumptions on camera orientation, you will need a digital elevation model (unless you also assume the ground is perfectly flat), and also the size of your camera's imaging sensor. I'll try here to describe a simplified version of this process. Given the position (I ...


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Correct CRS for these coordinates is EPSG:22287 (Cape / Lo27). Conversion from projected coordinates to EPSG:4326 (WGS 84) can be done at epsg.io: https://epsg.io/transform#s_srs=22287&t_srs=4326&x=58958.4440060&y=2491707.7922860 When converting, you have to swap X and Y. For example, for first coordinate A=Y59665 X2493871, when converting, it ...


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