2

I am trying to build a fast query to PostgreSQL. My raster (DEM) is 1.6 GB, about 2.5 cm precision...With a smaller DEM it was ok, about 20 seconds to query a 300m radius elevations. Now with this larger raster it is not even responding, or at least not within a day... My queries are structured this way:

WITH pairs(x,y) AS (
    VALUES (-74.61067886106919,45.60987140366732), 
           (-74.61068132465692,45.60987191852093)
) 
SELECT ST_Value(rast, ST_SetSRID(ST_MakePoint(x, y), 4326)) AS height 
FROM   alfred2 rs 
CROSS JOIN pairs 
WHERE  ST_Intersects(rs.rast, ST_SetSRID(ST_MakePoint(x, y), 4326));

This one with only a few points already takes like over 30 seconds... and I need a lot more points to calculate line-of-sight in my JavaScript program.

I was thinking of using ST_Clip to clip the raster prior to query but can't figure out how to do that for a circle of 250 meters around a lat,lng.

NOTE: I reloaded the DEM with 10x10 and The result of EXPLAIN ANALYSE:

Gather  (cost=1000.00..6964763.37 rows=1890080 width=8) (actual time=7500.324..7505.978 rows=2 loops=1)
   Workers Planned: 2
   Workers Launched: 2
   ->  Nested Loop  (cost=0.00..6774755.37 rows=787533 width=8) (actual time=6970.136..7435.628 rows=1 loops=3)
         Join Filter: st_intersects(rs.rast, st_setsrid(st_makepoint(("*VALUES*".column1)::double precision, ("*VALUES*".column2)::double precision), 4326), NULL::integer)
         Rows Removed by Join Filter: 1890075
         ->  Parallel Seq Scan on alfred5_10x10 rs  (cost=0.00..200821.00 rows=1181300 width=472) (actual time=0.038..227.874 rows=945038 loops=3)
         ->  Values Scan on "*VALUES*"  (cost=0.00..0.03 rows=2 width=64) (actual time=0.000..0.001 rows=2 loops=2835113)
 Planning Time: 0.156 ms
 JIT:
   Functions: 12
   Options: Inlining true, Optimization true, Expressions true, Deforming true
   Timing: Generation 2.133 ms, Inlining 123.100 ms, Optimization 150.016 ms, Emission 83.455 ms, Total 358.705 ms
 Execution Time: 7506.925 ms

11
  • st_buffer((st_setsrid(st_makepoint(x,y),4326))::geography,250)
    – jbalk
    Commented Sep 7, 2021 at 19:09
  • also make sure you have a spatial index on the raster column
    – jbalk
    Commented Sep 7, 2021 at 19:13
  • How did you load the raster? i.e. was it tiled with the -t option? Commented Sep 7, 2021 at 23:09
  • Can you show the output of \d alfred2 and \d pairs ? Commented Sep 8, 2021 at 6:20
  • You should attach the result of the explain of the request. This is just a supposition, but I think the query planner is not able to properly optimise this requeste due to the Where coupled with a Cross join. It probably has to perform a Nested Loop on the table and then filtering, hence the long query time. If this is really what is happening I think that replacing the "CROSS JOIN <table> WHERE <filtrer>" part with "JOIN <table> ON<filtrer>" should work.
    – Atm
    Commented Sep 8, 2021 at 7:49

1 Answer 1

1

Like said in comments, this query is particularly long because the planner does not consider it necessary to use a geographical index when executing the WHERE clause. Initially I thought it was either because the table had no index, or the statistics were not up to date, or because of the use of a CROSS JOIN. So I tested these queries on a large raster table (a 1m DEM of a full french departement [NUTS 3], ~5 500 km²) with a geometry index and updated statistics.

The adaptation of your request have a similar comportment,the query is very long and the query plan as very similar :

with pairs(x,y) as (
    values (980279.44, 6431129.89),
           (982573.24, 6429308.57)
)
SELECT st_value(rast, ST_SetSRID(ST_Point(x, y), 2154)) 
FROM rgealti_fxx_0892_6372_mnt_lamb93_ign69
cross join pairs
WHERE st_intersects(rast, ST_SetSRID(ST_Point(x, y), 2154));

The planner doesn't use a index, despite the fact that only two lines out of 600,000 need to be selected.

Gather  (cost=1000.00..1441615.80 rows=399801 width=8)
  Workers Planned: 2
  ->  Nested Loop  (cost=0.00..1400635.70 rows=166584 width=8)
        Join Filter: st_intersects(rgealti_fxx_0892_6372_mnt_lamb93_ign69.rast, st_setsrid(st_point(("*VALUES*".column1)::double precision, ("*VALUES*".column2)::double precision), 2154), NULL::integer)
        ->  Parallel Seq Scan on rgealti_fxx_0892_6372_mnt_lamb93_ign69  (cost=0.00..10075.76 rows=249876 width=20)
        ->  Values Scan on "*VALUES*"  (cost=0.00..0.03 rows=2 width=64)

But with small changes it's works :

WITH points(geom) as (
    values (ST_SetSRID(ST_Point(980279.44, 6431129.89), 2154)),
           (ST_SetSRID(ST_Point(982573.24, 6429308.57), 2154)),
           (ST_SetSRID(ST_Point(926078.71, 6371869.75), 2154))
)
SELECT rid, geom as select_point, st_value(rast, geom) as height, st_envelope(rast) as raster_bbox
FROM rgealti_fxx_0892_6372_mnt_lamb93_ign69
Join points
on  st_intersects(rast, geom);

Unfortunately, I am unable to explain why this second version uses an index. Maybe these can't work when a point is created on the fly, but it seems to me that it is possible in other situations, this is a question to be explored.

Nested Loop  (cost=0.29..1330.14 rows=600 width=76) (actual time=0.855..1.335 rows=3 loops=1)
      ->  Values Scan on "*VALUES*"  (cost=0.00..0.04 rows=3 width=32) (actual time=0.003..0.005 rows=3 loops=1)
      ->  Index Scan using rgealti_fxx_0892_6372_mnt_lamb93_ign69_st_convexhull_idx on rgealti_fxx_0892_6372_mnt_lamb93_ign69  (cost=0.29..392.67 rows=20 width=24) (actual time=0.177..0.178 rows=1 loops=3)
            Index Cond: ((rast)::geometry && "*VALUES*".column1)
            Filter: _st_intersects("*VALUES*".column1, rast, NULL::integer)
    Planning Time: 0.560 ms
    Execution Time: 1.381 ms
1
  • 1
    A B S O L U T E L Y amazing, went from 7506.925 ms to Execution Time: 0.324 ms on my dev server! Commented Sep 13, 2021 at 15:35

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.