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In QGIS I have a list of points, each with a town it's located in and a status, either 'new' or 'existing'. So something like:

ID town type
01 Alicetown new
02 Alicetown new
03 Alicetown existing
04 Bobsburgh existing
05 Bobsburgh new

I can count how many points are in each town (Alicetown: 3, Bobsburgh: 2), but I'd like to count how many new and existing points are in each (Alicetown: New: 2, Existing: 1; Bobsburgh: New: 1, Existing: 1).

I could just make a column for existing and new but I figured there has to be an easier way.

Is there a way to achieve what I'm trying to do? I've tried SQL but I don't really know enough about it to get it to do what I want.

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  • 2
    Welcome to GIS SE. As a new user, please take the Tour. Please Edit the Question to show what SQL you tried, and what the result was, , so we can recommend a fix.
    – Vince
    Commented Dec 7, 2022 at 2:52
  • What are you expecting to achieve as the final output, a new column in existing layer, a new table, a new layer etc. ?
    – Taras
    Commented Dec 7, 2022 at 6:10
  • I'm probably expecting a table but really, I'd be okay with any kind of output. Another comment already helped me to achieve what I was trying to do but I'd gladly learn about other methods too. Commented Dec 7, 2022 at 15:47
  • What should I do when someone answers my question?
    – Bera
    Commented Dec 17, 2022 at 10:33

2 Answers 2

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Perhaps the simplest way is to use the Statistics by category tool. It creates a new table, summarising your input.

Select the fields by which to categorise, and leave Field to calculate statistics on blank to get the count only:

enter image description here

Result

enter image description here

1
  • Oh yea...that's what I was trying to do. I did the initially count with this tool but it never occurred to me I could just add more fields with categories :'D Thanks a lot! Commented Dec 7, 2022 at 15:45
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With SQL and a Virtual Layer you can try:

select town, type, count(*) pointcount, geometry
from pointlayer
group by town, type

enter image description here

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