1

I'm looking for historical traffic data on a decently large city.
Specifically I need data points that can be used to infer the distribution of vehicle speeds across each road, but I don't want the data to be pre-processed (i.e., it should be coming in the form of individual samples, instead of pre-fit distributions to the data).
It doesn't really matter where the data is from, any major city should be fine -- I just need the the traffic pattern to be interesting for analysis.

Is there any source from which I can obtain such data for free and without too much difficulty?
(Ideally it wouldn't be too difficult to map the roads to those from OpenStreetMaps.)

Improve this question
7
  • Define a "decently large city." London, UK or Mexico City.
    – Mapperz ♦
    Commented Jun 12, 2014 at 4:15
  • @Mapperz: I mean something with an interesting traffic pattern, where routing is actually a problem of interest. San Francisco, Luxembourg, etc. would be great.
    – user541686
    Commented Jun 12, 2014 at 4:15
  • like dot.ca.gov/dist4/highwayops/hoindex.html
    – Mapperz ♦
    Commented Jun 12, 2014 at 4:18
  • @Mapperz: I can't find anything on that page that has raw data. It only seems to be the average over many vehicles, which tells me nothing about the shapes of the distributions. Maybe I missed what part of the page you were referring to?
    – user541686
    Commented Jun 12, 2014 at 4:33
  • 1
    To obtain raw data, you may have to call the specific DOT you are interested in getting data for.
    – artwork21
    Commented Jun 12, 2014 at 12:37

1 Answer 1

Reset to default
1

Here is some historic traffic data from San Francisco:

http://www.mtc.ca.gov/maps_and_data/datamart/traffic/

AND

ftp://ftp.abag.ca.gov/pub/mtc/planning/traffic/

Improve this answer
1
  • Thanks, appreciate it. Unfortunately it doesn't look like they have individual vehicle speeds, but are rather just reporting total counts and mean/standard deviations which isn't what I was looking for.
    – user541686
    Commented Jun 12, 2014 at 18:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.