6

In my QGIS python plugin I want to add a background map (if the user haven't added one), hence I think I missing something in the url for the Tiles/wms service.. (the function returns invalid layer) Any suggestions?

    sources = [layer.source() for layer in QgsProject.instance().mapLayers().values()]
    print(sources)
    source_found = False
    for source in sources:
        if 'xyz&url' in source:
            source_found = True
            print('found')
    if not source_found:
        print('adding')
        urlWithParams = 'type=xyz&url=http://a.tile.openstreetmap.org/%7Bz%7D/%7Bx%7D/%7By%7D.png&zmax=19&zmin=0&crs=EPSG3857'
        rlayer = QgsVectorLayer(urlWithParams, 'OpenStreetMap', 'wms')
        if rlayer.isValid():
            QgsProject.instance().addMapLayer(rlayer)
        else:
            print('invalid layer')
4
  • 1
    What version of QGIS, are you using ? Commented Aug 11, 2018 at 7:39
  • QGIS3.. (I know how to add it with XYZ Tiles manually)
    – axel_ande
    Commented Aug 11, 2018 at 14:01
  • python to load xyz tiles raw.githubusercontent.com/klakar/QGIS_resources/master/… > sources.append(["connections-xyz","OpenStreetMap Standard"
    – Mapperz
    Commented Aug 15, 2018 at 4:32
  • I know, it is a very nice script how to add the tiles to the browser, hence I would like to add it as a layer.
    – axel_ande
    Commented Aug 15, 2018 at 7:48

1 Answer 1

11
+50

Tiles/WMS sources give you raster data. So, you have to use QgsRasterLayer() instead of QgsVectorLayer().

Try in this way:

...
    rlayer = QgsRasterLayer(urlWithParams, 'OpenStreetMap', 'wms') # EDIT THIS LINE

    if rlayer.isValid():
        QgsProject.instance().addMapLayer(rlayer)
    else:
        print('invalid layer')
1
  • I knew it was an easy fix! Thx
    – axel_ande
    Commented Aug 21, 2018 at 8:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.