Find features within given coordinates and distance using MySQL

Question

I have a MySQL table with user name, latitude and longitude of the user.

I would like to get a list of users who are inside the circle or square of a given latitude and longitude with given distance. For example, my input Lat = 78.3232 and Long = 65.3234 and distance = 30 miles. I would like to get the list of users who are inside 30 miles distance from the point 78.3232 and 65.3234.

Is it possible to solve this with single query? Or can you give me a hint start solving this query?

Answer 1

Mapperz's answer is invalid. Sinus must be calculated from latitude and NOT from longitude. So corect SQL statement is:

SELECT
    id, (
      3959 * acos (
      cos ( radians(78.3232) )
      * cos( radians( lat ) )
      * cos( radians( lng ) - radians(65.3234) )
      + sin ( radians(78.3232) )
      * sin( radians( lat ) )
    )
) AS distance
FROM markers
HAVING distance < 30
ORDER BY distance
LIMIT 0 , 20;

Answer 2

The SQL statement that will find the closest 20 locations that are within a radius of 30 miles to the 78.3232, 65.3234 coordinate. It calculates the distance based on the latitude/longitude of that row and the target latitude/longitude, and then asks for only rows where the distance value is less than 30 miles, orders the whole query by distance, and limits it to 20 results. To search by kilometers instead of miles, replace 3959 with 6371.

SELECT
  id, (
    3959 * acos (
      cos ( radians(78.3232) )
      * cos( radians( lat ) )
      * cos( radians( lng ) - radians(65.3234) )
      + sin ( radians(78.3232) )
      * sin( radians( lat ) )
    )
  ) AS distance
FROM markers
HAVING distance < 30
ORDER BY distance
LIMIT 0 , 20;

This is using the Google Maps API v3 with a MySQL backend which your already have.

https://developers.google.com/maps/articles/phpsqlsearch_v3#findnearsql

Answer 3

It's 2020, you should be using the built in spatial function of the RDBS. In this case you are after the ST_Distance function.

-- geo column in users table is of Geometry data type, with a spatial index
SET @g1 = ST_SRID(POINT(78.3232, 65.3234), 4326);
SELECT * from users WHERE ST_Distance(users.geo, @g1, 'foot') < 158400; -- 5280 feet per mile

Answer 4

It might be base to create a function .. so you can reuse it other other areas. Also would make your query a bit cleaner... At least that is my 2 cents.

DELIMITER $$

CREATE FUNCTION calcDistance(lat FLOAT, lng FLOAT, pnt_lat FLOAT, pnt_lng FLOAT)
    RETURNS FLOAT
BEGIN

    DECLARE dist FLOAT;
    SET dist =
          3959 * acos(
                cos(radians(pnt_lat))
                * cos(radians(lat))
                * cos(radians(lng) - radians(pnt_lng))
            + sin(radians(pnt_lat))
                    * sin(radians(lat))
          );

    RETURN dist;

END

Answer 5

Here is my variant of query, seems a little bit easier (http://dexxtr.com/post/83498801191/how-to-determine-point-inside-circle-using-mysql)

SELECT 
    *
FROM 
    `locator`
WHERE
    SQRT(POW(X(`center`) - 49.843317 , 2) + POW(Y(`center`) - 24.026642, 2)) * 100 < `radius`